[dami]

Originally Posted by harleyb

F=ma, right? Assuming a constant force, (this is plausible at least in the gas pistols i've studied because of the floating/backpressure valve) acceleration is inversely proportional to the mass, a=F/m
final velocity can be found with vf^2 = vi^2 + 2ad
assuming a 500mm barrel vf = sqrt(0 + 2*0.5*F/m) = sqrt(F/m)
so hypothetical exit velocity of a 0.2g BB compared to a 0.36g is ?F/0.45 : ?F/0.6
this means that the 0.36g BB will be about 25% slower, even though it's almost 75% heavier.

if your M700 is shooting a 0.2g at 500FPS, it should hypothetically be shooting a 0.36g at 375FPS, and not the 277FPS you stated.

Edit: I forgot to mention that all of this is completely invalidated because of hopup. To get a straight flight path, the heavier your BB, the more hop needs to be applied. This gets into extremely complicated physics.

That's what I wanted ..prove me wrong. I'll recheck my calculations tonight. I see where you are going with this. Hopefully next time I'll get them right.
Thanks you and all,
Danny